In order for 20 mL of 0.20 M KMnO4 solution to completely react, 3 m.mol of chlorite anion are needed. by a redox process.
Reduction
MnO−4+4H++3e−→MnO2(s)+2H2O(l) I (i)
Oxidation ClO2 + 2 H2 O + ClO4 + 4 H + 4 e (ii)
Overall
4×(i)+3×(ii)4MnO−4+3ClO−2+4H+→4MnO2(s)+3ClO−4+2H2O(l)
Moles of KMnO4 equal 20 10 3L, 0.20 mol, and 1 = 4.0 10 3mol.
According to the equation, we require 3/4 equiv (or 4.0 10 3 mol) of chlorite anion.
Molarity (M), which is determined by dividing the solute's mass in moles by the volume of the solution in liters, is the most widely used unit to express solution concentration: liters of solution/moles of solute equals M. One liter of a solution with a 1 molar concentration (1.00 M) contains 1.00 moles of solute.
Moles of solute divided by kilograms of solvent equals molality. Adding moles of a solvent = 3 and mass of solvent = 0.5 kg , we obtain molality = 3 / 0.5 = 6 mol/kg .
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