Respuesta :
The time taken by the error to hit the ground is 1 second and the arrow goes to a distance of 45 m.
The height of the arrow is 4.9 metre above the ground and the initial speed of the arrow is 45m/s.
The path of the arrow will be a projectile.
a) The time of flight of the arrow to hit the ground is given by,
T = √(2H/g)
H is the height of the arrow,
g is the acceleration due to gravity.
Now, putting all the values,
T = √(2×4.9/9.8)
T = 1 seconds.
The arrow will take one second to hit the ground.
b) The horizontal range of the projectile for the arrow is given by,
R = UT
U is the initial speed,
T is the time of flight.
Putting values,
R = 45 × 1
R = 45 meters
So, the arrows goes till a distance of 45 meters.
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