Respuesta :

first factor 3 out of 3-9i giving

[tex]3(1-3i)[/tex]

then the original mutiplication would be

[tex](2i-4)\times3(-3i+1)[/tex]

Now factor 2 out of 2i-4 giving

[tex]2(i-2)[/tex]

Then the original multiplication would be

[tex]2(i-2)3(-3i+1)[/tex][tex]undefined[/tex]

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