We want to solve the following equation
[tex]3\cdot(3y\text{ -15)=0}[/tex]
We will start by dividing both sides by 0. So we get
[tex]3y\text{ - 15=}\frac{0}{3}=[/tex]
Now, we add 15 on both sides, so we get
[tex]3y=0+15=15[/tex]
Finally, we divide both sides by 3. So we get
[tex]y=\frac{15}{3}=5[/tex]
so the value is y=5
