We will have the following:
From the information provided we determine that:
Total distance: 1880 mi
Plane speed: x
Plane 1 speed: x + 40mph
Time: 2 h
We recall that distance is given by:
[tex]d=s\ast t[/tex]Where "s" is speed and "t" is time. Then:
[tex]\begin{gathered} (x+60)(2)+(x)(2)=1880\Rightarrow2x+120+2x=1880 \\ \\ \Rightarrow4x=1760\Rightarrow x=440 \end{gathered}[/tex]So, plane 1 travels at 480 mph and plane 2 travels at 440 mph.
