Given:
[tex]4x+7y=28[/tex]
To fill the table:
Explanation:
Substituting x = 0 in the given equation we get,
[tex]\begin{gathered} 7y=28 \\ y=4 \end{gathered}[/tex]
Substituting y = 0 in the given equation we get,
[tex]\begin{gathered} 4x=28 \\ x=7 \end{gathered}[/tex]
So, the points are
[tex](0,4),(7,0)[/tex]
Using the points, let us find the slope of the line.
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{0-4}{7-0} \\ m=\frac{-4}{7} \end{gathered}[/tex]
Therefore, the slope for the given equation is,
[tex]m=\frac{-4}{7}[/tex]
Final answer:
• When x = 0; y becomes 4.
,
• When y = 0; x becomes 7.
And
• The slope for the given equation is,
[tex]m=\frac{-4}{7}[/tex]
