find the distance between ivy’s house and the supermarket and the distance between the supermarket and the bank. each distance is rounded to the nearest meter.

find the distance between ivys house and the supermarket and the distance between the supermarket and the bank each distance is rounded to the nearest meter class=

Respuesta :

Answer:

The distance between the Supermarket and the bank is 854 meters

The distance between Ivy’s house and the Supermarket is 1,014 meters

Explanation:

We were given the following information:

Pont A represents Ivy's house

Point B represents the Supermarket

Point C represents the Bank

[tex]\begin{gathered} m\angle A=32^{\circ} \\ AB=c=? \\ BC=a=? \\ m\angle B=109^{\circ} \\ AC=b=1,523m \\ m\angle C=180-(109+32)=180-141=39^{\circ} \\ m\angle C=39^{\circ} \end{gathered}[/tex]

We were given 2 known angles and 1 known side. We will thus solve using Sine Rule as shown below:

[tex]\begin{gathered} \frac{Sin(A)}{a}=\frac{Sin(B)}{b}=\frac{Sin(C)}{c} \\ \frac{Sin(32^{\circ})}{a}=\frac{Sin(109^{\circ})}{1,523} \\ \text{Cross multiply, we have:} \\ a\times Sin(109^{\circ})=1,523\times Sin(32^{\circ}) \\ a=\frac{1,523\times Sin(32^{\circ})}{Sin(109^{\circ})} \\ a=853.57\approx854 \\ a=854m \end{gathered}[/tex]

Therefore, the distance between the Supermarket and the bank is 854 meters

We will proceed further:

[tex]\begin{gathered} \frac{Sin(A)}{a}=\frac{Sin(B)}{b}=\frac{Sin(C)}{c} \\ \frac{Sin(39^{\circ})}{c}=\frac{Sin(109^{\circ})}{1,523} \\ \text{Cross multiply, we have:} \\ c\times Sin(109^{\circ})=1,523\times Sin(39^{\circ}) \\ c=\frac{1,523\times Sin(39^{\circ})}{Sin(109^{\circ})} \\ c=1,013.68\approx1,014 \\ c=1,014m \end{gathered}[/tex]

Therefore, the distance between Ivy’s house and the Supermarket is 1,014 meters

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