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Given collinear points A,B,C such the coordinate of endpoints A and C are A(-4) and C(10). What is the coordinate of point B of segment AC that is partitioned in a ratio of 2 to 5

Respuesta :

Point A (-4) and C(10)

Point B is partitioned in a ratio of 2 to 5​

let the distance AB = x

The distance AC = 4 + 10 = 14

So, the distance BC = 14 - x

So,

AB : BC

2 : 5

x : 14 - x

So,

using the ratio and proportional

2(14 - x) = 5x

28 - 2x = 5x

28 = 7x

x = 28/7 = 4

so,

The coordinates of B = -4 + 4 = 0

Point B is (0)

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