Given:
• Number of turns = 10400 turns
,• Current = 21.0 A
Let's find the strength of the magnetic field.
To find the strength in the magnetic field, apply the formula:
[tex]B=\mu_onI[/tex]Where:
• B is the magnetic field
,• μ₀ is the permeability of free space.
,• n is the number of turns.
,• I is the current.
Thus, we have:
[tex]B=(4\pi\times10^{-7})*10400*21[/tex]Solving further, we have:
[tex]B=0.274\text{ T}[/tex]Therefore, the strength of the magnetic field is 0.274 T.
ANSWER:
0.274 T.
