We have the following current and resistance:
[tex]\begin{gathered} i=4+j2 \\ R=2-j3 \end{gathered}[/tex]Where 'j' represents the imaginary number. The voltage of a circuit is given by the product of the current and resistance. To find the voltage of this circuit we just need to multiply those two values:
[tex]V=i\mathrm{}.R=(4+j2)\mathrm{}(2-j3)=8-8j-6j^2=8-8j+6=14-8j[/tex]Then, this is our answer. The voltage is:
[tex]14-8j[/tex]