A rational function has a vertical asymptote when x becomes a value that makes the denominator equal to 0,
for f(x),
[tex]\begin{gathered} x+4=0 \\ x=-4 \end{gathered}[/tex]
for g(x),
[tex]x=0[/tex]
for h(x),
[tex]\begin{gathered} 2x^2+11x+12=0 \\ using\text{ the quadratic} \\ x=\frac{-11\pm\sqrt{11^2-4\times2\times12}}{2(2)} \\ x_1=-\frac{3}{2};x_2=-4 \end{gathered}[/tex]
Answer:
The functions f(x) and h(x) have vertical assymptotes at x=-4
