Respuesta :

The initial expression is:

[tex]\int (t-5)^3\text{ dt}[/tex]

First we can expant cube so:

[tex]\int t^3-15t^2+75t-125[/tex]

and now we can integrate so:

[tex]\frac{t^4}{4}-5t^3+\frac{75t^2}{2}-125t+C[/tex]

So is option B

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