Let a be the missing value. Then,
[tex]2\frac{3}{12}+\frac{3}{a}=2\frac{5}{8}[/tex]Therefore,
[tex]\frac{3}{a}=2\frac{5}{8}-2\frac{3}{12}=2\frac{5}{8}-2\frac{1}{4}=2\frac{5}{8}-2\frac{2}{8}=(2-2)\frac{5-2}{8}=\frac{3}{8}[/tex]That is
[tex]\begin{gathered} \frac{3}{a}=\frac{3}{8} \\ \text{ Hence,} \\ a=8 \end{gathered}[/tex]Therefore, the missing value is 8
