Solution:
The algebraic expression given is;
[tex]\begin{gathered} a^2-3bc \\ \text{where;} \\ a=-5 \\ b=-4 \\ c=10 \end{gathered}[/tex]
Substituting these values into the expression;
[tex]\begin{gathered} a^2-3bc=(-5)^2-3(-4)(10) \\ =25-3(-40) \\ =25+120 \\ =145 \end{gathered}[/tex]
Therefore, the value is 145.
