Respuesta :
Step 1
Given; On October 23, 2011, one U.S. dollar was worth 49.84 Indian rupees.
(a) On that date, how many rupees was 143.28 dollars worth?
Round your answer to the nearest hundredth of a rupee.
(b) On that date, how many dollars was 129.02 rupees worth?
Round your answer to the nearest hundredth of a dollar.
Step 2
A) we use the ratio below.
[tex]\begin{gathered} \frac{1dollar}{143.28\text{ dollars}}=\frac{49.84rupees}{x\text{ rupees}} \\ cross\text{ multiply} \end{gathered}[/tex][tex]x=143.28(49.48)\approx7141\text{ rupees }[/tex][tex]x=143.28(49.48)\approx7141\text{ rupees }[/tex]B) We solve using the ratio below
[tex]\frac{1\text{ dollar}}{x}=\frac{49.84}{129.02}[/tex][tex]\begin{gathered} 129.02=49.84x \\ \frac{49.84x}{49.84}=\frac{129.02}{49.84} \\ x\approx\text{ \$2.59} \end{gathered}[/tex]Answer;
[tex]\begin{gathered} A)\text{ 7141 rupees} \\ B)\text{ \$2.59} \end{gathered}[/tex]