Given a right angled triangle LMN;
Where MN is the hypothenus;
let LM be the opposite;
then LN is the adjacent.
By the pythagoras theorem;
[tex]\begin{gathered} \text{Where h=hypotenus, o=opposite and a=adjacent} \\ h^2=o^2+a^2 \\ o^2=h^2-a^2 \\ a^2=h^2-o^2 \end{gathered}[/tex][tex]\begin{gathered} h=33,\text{ o=11 and a=LN} \\ (LN)^2=33^2-11^2 \end{gathered}[/tex]
CORRECT OPTION: D
