Let's draw the situation:
Because the ground and the building make a 90° angle, we have a right triangle. We know one angle and its adjacent leg, and we want the opposite leg. Thus, we can use the tangent of the angle:
[tex]\begin{gathered} \tan 38\degree=\frac{h}{160} \\ h=160\tan 38\degree\approx160\cdot0.781286\approx125.006 \end{gathered}[/tex]So, the height of the building is approximately 125.006 m.
