use the Law of Cosine to solve for the missing angle in the triangle. Round to the nearest whole degree!!! I need help step by step tried to solve but want to make sure it's right
To find x, we use the law of cosines
[tex]16^2=22^2+8^2-2\cdot22\cdot8\cdot\cos x[/tex]Now, we solve for x
[tex]\begin{gathered} 256=484+64-352\cdot\cos x \\ 256=548-352\cdot\cos x \\ 256-548=-352\cdot\cos x \\ -\frac{292}{-352}=\cos x \\ x=\cos ^{-1}(\frac{292}{352}) \\ x\approx34.2 \end{gathered}[/tex]