The perimeter of a triangle is 69 cm. The longest side is 3 cm less than the sum of the other two sides. Twice the shortest side is 9 cm less than the longest side. Find the length of each side of the triangle.
a =33 longest side
c=24 middle side
b=12 shortest side
1) Gathering the data
2p = 69
a= (b+c)-3
2c= 9 -a
c = (9-a)/2
a+b+c = 69
2) Plugging in the equation a+b+c = 69
(b+c)-3 + b +c = 69
b+c -3 +b+c = 69
2b +2c =72
2(b+c)=72
b+c=36
a = 36 -3
a=33
c=(33-9)/2
c=24/2
c=12
a =33 longest side
c=24 middle side
b=12 shortest side