We will have the following:
We remember that the distance for a linear accelerated motion is given by the expression:
[tex]d=v_it+\frac{1}{2}at^2[/tex]
Here "d" is the distance, "vi" is the initial velocity (In our case it starts at rest so 0 m/s), "t" is the time and "a" is the acceleration at which the object is subjected, so:
[tex]d=(0m/s)(5.00s)+\frac{1}{2}(10.0m/s^2)(5.00s)^2\Rightarrow d=125.0m[/tex]
So, the distance the car travels in those 5 seconds is 125.0 m.
