Given,
The load at point C, C=3200 N
The load at point D, D=1500 N
The distance between point B and D, d₁=2 ft
The distance between point B and C, d₂=6 ft
The distance between point A and point B, d₃=10 ft
The moment of the load at point C with B as the center of moments is given by,
[tex]M_C=C\times d_2[/tex]
On substituting the known values,
[tex]\begin{gathered} M_C=3200\times6 \\ =19200\text{ N ft} \end{gathered}[/tex]
The moment of the load at point C is 19200 N·ft
The moment of the load at point C with B as the center of moments is
