Answer:
(a) (r o q)(7) = 8
(b)
Explanation:
Given the functions:
[tex]\begin{gathered} q(x)=x^2+6 \\ r(x)=\sqrt[]{x+9} \end{gathered}[/tex]
Part A
[tex](r\circ q)(7)=r\lbrack q(7)\rbrack[/tex]
First, evaluate q(7).
[tex]q(7)=7^2+6=49+6=55[/tex]
Therefore:
[tex]\begin{gathered} (r\circ q)(7)=r\lbrack q(7)\rbrack=r(55) \\ r(55)=\sqrt[]{55+9}=\sqrt[]{64}=8 \\ \implies(r\circ q)(7)=8 \end{gathered}[/tex]
Part B
