Consider that the possible outcomes are 1, 2, 3, 4, 5, 6, 7, 8.
The outcomes favorable to event A ae 2, 4, 6, 8.
So the probability of event A is given by,
[tex]P(A)=P\mleft(2\mright)+P\mleft(4\mright)+P\mleft(6\mright)+P\mleft(8\mright)[/tex]Substitute the values from the table,
[tex]\begin{gathered} P\mleft(A\mright)=0.099+0.021+0.009+0.442 \\ P(A)=0.571 \end{gathered}[/tex]Thus, the probability of event A is 0.571
