Explanation
We are required to determine the bearing of X from Z from theh given information.
This is achieved thus:
From the diagrammatic representation, let d km represent the equal distance from Y to X and from Y to Z.
According to angle Z, we have:
[tex]\begin{gathered} \tan\theta=\frac{opposite}{adjacent} \\ \tan Z=\frac{d}{d} \\ tanZ=1 \\ Z=\tan^{-1}(1) \\ Z=45\degree \end{gathered}[/tex]
Therefore, the bearing of X from Z is:
[tex]\begin{gathered} Bearing=90\degree+45\degree \\ Bearing=135\degree \end{gathered}[/tex]
Hence, the answer is:
[tex]135\degree[/tex]
