determine the type and key parts of the graph of the function
ANSWER:
Parabola
Vertex (2, 0)
Parabola opens: upward
STEP-BY-STEP EXPLANATION:
We have the following function:
[tex]y=\mleft(x-2\mright)^2[/tex]Since x is squared, the form of the function is parabolic and having a plus sign in the dependent term, the parabola opens upwards.
The vertex would be when y = 0, since no parameter affects the function, therefore:
[tex]\begin{gathered} 0=(x-2)^2 \\ x-2=0 \\ x=2 \\ \text{ the vertex is:} \\ (2,0) \end{gathered}[/tex]