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A plane is landing at a speed of 67 m/s when it hits the runway. The plane's brakes provide an acceleration of -1.5 m/s/s for 45 seconds. What distance of runway does the plane need to stop?O2072 metersO89.7 meters1496 meters3138 metersI do not know how to solve this question

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ANSWER:

3rd option: 1496 meters

STEP-BY-STEP EXPLANATION:

Given:

Initial velocity (u) = 67 m/s

Time (t) = 45 s

Acceleration (a) = -1.5 m/s/s

We can determine the distance as follows:

[tex]\begin{gathered} d=ut+\frac{1}{2}at^2 \\ \\ \text{ We replacing:} \\ \\ d=67\cdot45+\frac{1}{2}\cdot-1.5\cdot45^2 \\ \\ d=3015-1518.75 \\ \\ d=1496.25\cong1496\text{ m} \end{gathered}[/tex]

The correct answer is 3rd option: 1496 meters

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