EXAMPLE A= 2 Using 3.14 for 7, A= 3.14(5)? = 78.5 cm? Area of o= TT 2 5cm Find the area of each circle. Use 3.14 for T. 6. 7.5 m 7: r=2 ft 5.1 18 in.Exercise 7

EXAMPLE A 2 Using 314 for 7 A 3145 785 cm Area of o TT 2 5cm Find the area of each circle Use 314 for T 6 75 m 7 r2 ft 51 18 inExercise 7 class=

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The formula to find the area of ​​a circle is:

[tex]\begin{gathered} A=\pi r^2 \\ \text{ Where A is the area and} \\ r\text{ is the radius of the circle} \end{gathered}[/tex][tex]\begin{gathered} \pi=3.14 \\ r=2\frac{1}{2}ft \end{gathered}[/tex]

As the radius of the circle is a mixed fraction then we are going to convert it to an improper fraction and thus be able to work more easily with this number:

[tex]2\frac{1}{2}=\frac{2\cdot2+1}{2}=\frac{4+1}{2}=\frac{5}{2}[/tex]

Now, you have:

[tex]\begin{gathered} r=2\frac{1}{2}ft \\ \text{ or} \\ r=\frac{5}{2}ft \end{gathered}[/tex]

And then:

[tex]\begin{gathered} A=\pi r^2 \\ A=3.14\cdot(\frac{5}{2}ft)^2 \\ A=3.14\cdot(\frac{5}{2})^2ft^2 \\ A=3.14\cdot\frac{5^2}{2^2}^{}ft^2 \\ A=3.14\cdot\frac{25}{4}^{}ft^2 \\ A=\frac{3.14}{1}\cdot\frac{25}{4}^{}ft^2 \\ A=\frac{3.14\cdot25}{4}^{}ft^2 \\ A=\frac{78.5}{4}ft^2 \\ A=19.63ft^2 \end{gathered}[/tex]

Therefore, the area of this circle will be 19.63 square feet.

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