Let us write the formula for the volume of a cone,
[tex]\text{The volume of a cone=}\frac{1}{3}\pi r^2h[/tex]Let us write out the given data,
[tex]\begin{gathered} \text{Volume of a cone=3}\pi x^3unit^3 \\ \text{height}=\text{xunit} \\ \text{radius}=r=\text{?} \end{gathered}[/tex]Let us now solve for the radius by substituting the given data,
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