Answer:
A'(6,-1), B'(-4,1) and C'(2,3)
Explanation:
The vertices of triangle ABC are: A(5, - 3), B(-5, - 1), and C(1, 1).
The translation rule is interpreted below:
[tex](x,y)\rightarrow(x+1,y+2)[/tex]
Therefore, the vertices of the image of ABC will be:
[tex]\begin{gathered} A^{\prime}(5+1,-3+2)=(6,-1) \\ B^{\prime}(-5+1,-1+2)=(-4,1) \\ C^{\prime}(1+1,1+2)=(2,3) \end{gathered}[/tex]
The vertices of triangle A'B'C' are:
A'(6,-1), B'(-4,1) and C'(2,3)
