MeghaH186927
MeghaH186927
04-11-2022
Mathematics
contestada
) Endpoint: (9,-10), midpoint: (4,8)
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KasaundraF47017
KasaundraF47017
04-11-2022
[tex]\begin{gathered} \Rightarrow(4,8)=(\frac{9+x}{2},\frac{-10+y}{2}) \\ \Rightarrow4=\frac{9+x}{2}\Rightarrow x=-1 \\ \Rightarrow8=\frac{-10+y}{2}\Rightarrow y=26 \\ \text{The other endpoint is (-1,26)} \end{gathered}[/tex]
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