Given:
[tex]\text{ The equation of a circle }(x-1)^2+(y+3)^2=16[/tex]
Required:
Use the equation of the circle given above to find the center and radius.
Explanation:;
We know the standard equation of the circle
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{ Where, }center(h,k)\text{ and }radius(r) \end{gathered}[/tex]
Now ,
in given equation, center is (1, -3) and radius is 4.
Answer:
Answered the question.
