Given
[tex]y=\log_2x[/tex]
Find
Plot the points on the graph
Explanation
At x = 1/2
[tex]y=\log_2(\frac{1}{2})=\log_2(2^{-1})=-1[/tex]
At x = 1 ,
[tex]y=\log_21=\log_2(2^0)=0[/tex]
at x =2
[tex]y=\log_22=\log_2(2^1)=1[/tex]
at x = 4
[tex]y=\log_24=\log_2(2^2)=2[/tex]
at x = 8
[tex]y=\log_28=\log_2(2^3)=3[/tex]
so , by potting the points on the graph ,
Final Answer
The above graph is the answer.
