We are given a piece-wise function so to evaluate f(x), we need to identify which set of operations should be used by knowing where the value of x falls under.
We are looking for f(3) and 3 ≥ 3 so we use
[tex]f(x)=-\frac{1}{3}x-8[/tex]
We substitute 3 for the x to get:
[tex]\begin{gathered} f(3)=-\frac{1}{3}(3)-8 \\ \\ f(3)=-1-8 \\ \\ f(3)=-9 \end{gathered}[/tex]
The answer is -9.
