Given the shown graph
the vertx is in the point V(0,1)
this means when x values = 0 then y-value=1
Option A and Option C match with this description
now let's check the x-intervals
x-intervals are given when x=0
then
Option A
[tex]y=-\frac{1}{24}x^2+1[/tex][tex]0=-\frac{1}{24}x^2+1[/tex][tex]24=x^2[/tex][tex]x=\sqrt{24}=\pm4.89[/tex]
since the x interval is greater than 4 this don't match with the parabola shown
then the correct answer is option C
[tex]y=-\frac{1}{12}x^2+1[/tex]
