.The function f is given by:
[tex]f(x)=\sec(x)[/tex][tex]\begin{gathered} f(\frac{\pi}{3})=2 \\ f(\frac{\pi}{2})=\frac{1}{0} \\ f(0)=1 \\ f(\frac{\pi}{4})=\sqrt{2} \\ \end{gathered}[/tex][tex]\text{ Since }\cos(x)=0\text{ at }x=\frac{\pi}{2},\text{ it follows that the function }f\text{ has a vertical asymptote at }\frac{\pi}{2}[/tex]Since f(0) = 1, it follows tha (0, 1) is on the line.
Hence, the correct answers are:
(0,1) is a point on the graph.
There is a vertical asymptote at x = /2.
