hello this is a trigonometry question hopefully you can help I did every thing else it's just the last one I can't get the reference angle for five in this question
1) Let's set a proportion to find 5 radians equivalence to degrees and then locate which quadrant
[tex]\begin{gathered} \theta=5 \\ \pi-----180\circ \\ 5------x \\ \\ x=\frac{5\text{ x 180}}{\pi} \\ x=286.5\text{ or }\frac{900}{\pi} \\ \end{gathered}[/tex]So since Quadrant IV is >270º and < 360º.
θ is in Quadrant IV
2) Let's find the Reference angle
Since the angle is in Quadrant IV, we subtract from 360º (or 2pi)
360º-286.5=73.5º
or
[tex]2\pi-\frac{900}{\pi}=\frac{2\pi-900}{\pi}[/tex]