Okay, here we got the following equation from the data:
m∠EFG=m∠EFN+m∠GFN
Replacing we get:
8y+15=4y-15+3y+59
Working we get:
8y-4y-3y=-15-15+59
y=29
And replacing this value in the equation we get:
m∠EFG=8y+15=8(29)+15=247
Finally we get that m∠EFG is the first option 247.
