To find:
The value of x in the triangle.
Solution:
In the given triangle, if we use the cosine rule for the triangle:
[tex]\begin{gathered} \cos x=\frac{25^2+19^2-24^2}{2(25)(19)} \\ \cos x=\frac{625+361-576}{950} \\ \cos x=\frac{410}{950} \\ x=\cos^{-1}(\frac{41}{95}) \\ x=64.43 \end{gathered}[/tex]
Thus, option D is correct.
