Answer:
x=4,8
Explanation:
Given the function, h(x) defined below:
[tex]h(x)=\frac{x^{2}-4 x-12}{x^{2}-12 x+32}[/tex]
The values of x that are NOT in the domain of h are the values for which the denominator is 0, i.e.
[tex]x^2-12x+32=0[/tex]
Solve the quadratic equation for x:
[tex]\begin{gathered} x^2-8x-4x+32=0 \\ x(x-8)-4(x-8)=0 \\ (x-4)(x-8)=0 \\ x-4=0\text{ or }x-8=0 \\ x=4\text{ or }x=8 \end{gathered}[/tex]
The values of x that are NOT in the domain of h are: x=4,8
