Suppose that goats have one gene that codes for color, where A is brown and a is white. The goats also have another gene that codes for height, where B is tall and b is short. If these two genes are unlinked, what is the probability that a cross between Aa Bb × Aa bb parents will produce three out of five offspring that are brown and short? Enter your answer as a decimal, rather than as a percentage.

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Oseni Oseni · Answer 1 · 2022-09-08T15:54:36+02:00

The probability that 3 out of 5 offspring from the cross will be brown and short does not exist or is zero.

A represents brown and a represents white.

B is tall while b is short.

AaBb x Aabb

Offspring

A_B_ (brown and tall) = 6/16 or 3/8

A_bb (brown and short) = 6/16 or 3/8

aaB_ (white and tall) = 2/16 or 1/8

aabb (white and short) = 2/16 or 1/8

In other words, the probability of producing offspring that are brown and short is 3/8.

Thus, the probability that 3 out of 5 offspring from the cross will be brown and short does not exist or is zero.

More on dihybrid crosses can be found here: https://brainly.com/question/1185199

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