Answer: 56.44°
Explanation:
Given:
- Let u represent the current speed of the plane, 1.2 Mach
Converting to SI Units (m/s):
= (1.2 mach)(340 ms^-1 / 1 Mach)
u = 408 m/s
- Speed of sound in air, v = 340 m/s
Find:
- Angle the wave front of the shock wave relative to the plane's direction of motion, θ
We have, sinθ = speed of sound / speed of object
sinθ = v / u
θ = sin^-1 (v / u)
= sin^-1 (340 / 408)
θ = 56.44°
