Substitute and Check:
[tex]y > 2x + 1 \\ 3 > 2(1) + 1 \\ 3 > 3 \\ false[/tex]
We can stop here and conclude that ( 1 , 3 ) is not a solution to this system, since it does not even satisfy the first equation, but check for the other one just in case:
[tex]y < - 3x \\ 3 < - 3(1) \\3 < - 3 \\ also \: false[/tex]
