kbgraham123
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Enzo and Zahra are playing a game. Their scores for five games are shown in the table below.

Enzo’s and Zahra’s Scores

Enzo’s Scores

39

47

46

50

38

Zahra’s Scores

37

33

45

30

45

Enzo’s mean score is 44. Zahra’s mean score is 38. The difference between the mean scores is about how many times the mean absolute deviation of the data sets, to the nearest whole number?

Respuesta :

Given the table that contains Enzo's and Zahra's scores for five games, we solve the required problem as follows:


The difference between the mean scores is 44 - 38 = 6
The difference between the mean scores is about the same size as the mean absolute deviation of the data sets
Eduard22sly

The difference between the mean scores is about 5 times the mean absolute deviation

Data obtained from the question

  • Enzo's scores: 39, 47, 46, 50, 38
  • Enzo's mean score = 44
  • Zahra’s scores: 37, 33, 45, 30, 45
  • Zahra’s mean score = 38
  • Comparison of mean and mean deviation =?

How to determine mean absolute deviation

For Enzo

  • Enzo's scores: 39, 47, 46, 50, 38
  • Enzo's mean score = 44
  • Absolute deviation = |(44 – 39) + (44 – 47) + (44 – 46) + ( 44 – 50) + (44 – 38)| = 22
  • Number of data = 5
  • Mean absolute deviation =?

Mean absolute deviation = Absolute deviation / Number of data

Mean absolute deviation = 22 / 5

Mean absolute deviation = 4.4

For Zahra

  • Zahra’s scores: 37, 33, 45, 30, 45
  • Zahra’s mean score = 38
  • Absolute deviation = |(38 – 37) + (38 – 33) + (38 – 45) + (38 – 30) + (38 – 45)| = 28
  • Number of data = 5
  • Mean absolute deviation =?

Mean absolute deviation = Absolute deviation / Number of data

Mean absolute deviation = 28 / 5

Mean absolute deviation = 5.6

How to determine the difference

  • Enzo's mean score = 44
  • Zahra’s mean score = 38
  • Difference in mean = 44 – 38 = 6
  • Mean absolute deviation for Enzo = 4.4
  • Mean absolute deviation for Zahra = 5.6
  • Difference in deviation = 5.6 – 4.4 = 1.2

Comparison of the differences

  • Difference in mean = 6
  • Difference in deviation = 1.2
  • Comparison =?

Comparison = Difference in mean / Difference in deviation

Comparison = 6 / 1.2

Comparison = 5

Thus, the difference between the mean score is 5 times the mean absolute deviation

Learn more about mean absolute deviation:

https://brainly.com/question/8974461

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