A 6.0 cm high elevation block is placed under one end of a 1.0 m long track. find the angle of elevation of the track.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below is the solution>;

short side is 0.06m, and hyp is 1 m
Sine is opposite/hyp
sinθ = 0.06/1
θ = 3.44º

Answer Link

isyllus isyllus · Answer 2 · 2019-09-30T14:20:13+02:00

Answer:

3.4°

Step-by-step explanation:

A 6.0 cm high elevation block is placed under one end of a 1.0 m long track.

Block is 6 cm high. It would stand vertically.

Stand one end of horizontal track 1 m long.

Please see the attachment for graph.

Let the elevation of block is Ф

In ΔABC, ∠B=90°

AB= 6 cm

BC = 1 m

First we change meter to centimeter. 1 m = 100 cm

So, BC = 100 cm

[tex]\tan\theta=\dfrac{AB}{BC}[/tex]

[tex]\tan\theta=\dfrac{6}{100}[/tex]

[tex]\theta=\tan^{-1}(0.06)[/tex]

[tex]\theta\approx 3.4^\circ[/tex]

Hence, The elevation of the track is 3.4°