Respuesta :
The Al to Cl ratio is [tex]\frac{0.0200}{0.060} = \frac{1}{3}[/tex]. Meaning that there is 1 Al to every 3 Cl, and so the empirical formula is [tex]AlCl_{3}[/tex].
Answer:
Empirical formula for the given elements = [tex]AlCl_3[/tex]
Explanation:
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
Moles of aluminum = 0.0200 mol
Moles of chlorine = 0.0600 mol
For empirical formula , divide the smallest number of moles from each moles of element.
Aluminium = [tex]\frac{0.0200 mol}{0.0200 mol} =1[/tex]
Calcium = [tex]\frac{0.600 mol}{0.0200 mol} =3[/tex]
Empirical formula for the given elements = [tex]AlCl_3[/tex]
