A ball weighing 100 n is shown suspended from a system of cords. what is the tension in the horizontal and angled cords at 50 degrees and 90 degrees 1

Respuesta :

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We use the the Newton's second law of motion: F=ma=0 (at equilibrium)

90 degrees:
F = T - W = 0
T = W = 100 N

50 degrees: If the angle is 50 degrees with the horizontal, then the angle of the cord with the vertical is 180 - 90 - 50 = 40 degrees. Then,

F = Tcos(4) - W =0
T = 100/cos(40)
T = 130.5 N
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