Answer:
Impulse, J = 72 kg-m/s
Explanation:
It is given that,
Mass of the ball, m = 8 kg
Initial velocity of the ball, u = 5 m/s
Final velocity of the ball, v = -4 m/s (as it rebounds back)
We need to find the impulse applied to the bowling ball. We know that impulse is equal to the change in momentum of an object i.e.
[tex]J=m(v-u)[/tex]
[tex]J=8\ kg\times (-4\ m/s-5\ m/s)[/tex]
J = -72 kg-m/s
Negative sign shows the impulse is applied in opposite direction. So, the correct t option is (c). Hence, this is the required solution.
