What's the answer? I don't know how to do it.
The required limits for the heads (a), (b), (c) are given by 4, 1, 4 respectively.
[tex]f(x)\left \{ {{4x-3} ,x < 1\atop {3x+1},x\geq 1} \right.[/tex]
Limit, can be defined nearby values of a variable at which the function has their exists.
a) [tex]\lim_{x \to 1+\y}3x+1\\[/tex]
⇒ 4
b) [tex]\lim_{x \to -1\y}4x-3\\[/tex]
⇒ 1
c) [tex]\lim_{x \to 1\y}3x+1\\[/tex]
⇒4
Thus, The required value of limits of a, b, c is given by 4, 1 ,4 respectively.
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