The value of x in the triangle is 28.1 degrees
How to solve for x?
The given triangle is a right triangle.
So, the relationship between the sides and angle x is:
sin(x) = opposite/hypotenuse
This gives
sin(x) = 8/17
Evaluate the quotient
sin(x) = 0.4706
Take the arc sin of both sides
[tex]x = \sin^{-1}(0.4706)[/tex]
Evaluate
x = 28.1
Hence, the value of x in the triangle is 28.1 degrees
Read more about right triangles at:
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