The tens digit is 3; the units digit is 3-1 = 2; and the number itself is 32.
Lets simplify the problem,
Let assume the "tens" digit be x
Then the "units" difference = (x-1), according to the condition.
Hence, the number itself is N = 10x + (x-1).
Then the number N+8 is 10x + (x-1) + 8 = 10x + x + 7 = 11x + 7.
From the last statement of the problem, we have this equation
[tex]N+8 = 8*(x+y),or11x + 7 = 8*(x+(x-1)).[/tex]
Simplify and find "x"
[tex]11x + 7 = 8*(2x-1)11x + 7 = 16x - 87 + 8 = 16x - 11x15 = 5xx = 15/5 = 3[/tex].
Thus the tens digit is 3; the units digit is 3-1 = 2; and the number itself is 32.
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